php判断xss攻击[网站编程]

//判断能否是xss攻击
function _xss_check() {
//urldecode解码已编码的 URL 字符串
//解码 过后的url串
$temp = strtoupper(urldecode(urldecode($_SERVER['REQUEST_URI'])));

if(strpos($temp, '<') !== false || strpos($temp, '"') !== false || strpos($temp, 'CONTENT-TRANSFER-ENCODING') !== false) {
die('报告:xss攻击');
}
return true;
}